=== Preventing Combinatorial Explosions

The terms bucket dynamically builds buckets based on your data; it doesn't know up front how many buckets will be generated. ((("combinatorial explosions, preventing")))((("aggregations", "preventing combinatorial explosions"))) While this is fine with a single aggregation, think about what can happen when one aggregation contains another aggregation, which contains another aggregation, and so forth. The combination of unique values in each of these aggregations can lead to an explosion in the number of buckets generated.

Imagine we have a modest dataset that represents movies. Each document lists the actors in that movie:

[source,js]

{ "actors" : [ "Fred Jones", "Mary Jane", "Elizabeth Worthing" ]

}

If we want to determine the top 10 actors and their top costars, that's trivial with an aggregation:

[source,js]

{ "aggs" : { "actors" : { "terms" : { "field" : "actors", "size" : 10 }, "aggs" : { "costars" : { "terms" : { "field" : "actors", "size" : 5 } } } } }

}

This will return a list of the top 10 actors, and for each actor, a list of their top five costars. This seems like a very modest aggregation; only 50 values will be returned!

However, this seemingly ((("aggregations", "fielddata", "datastructure overview")))innocuous query can easily consume a vast amount of memory. You can visualize a terms aggregation as building a tree in memory. The actors aggregation will build the first level of the tree, with a bucket for every actor. Then, nested under each node in the first level, the costars aggregation will build a second level, with a bucket for every costar, as seen in <>. That means that a single movie will generate n^2^ buckets!

[[depth-first-1]] .Build full depth tree image::images/300_120_depth_first_1.svg["Build full depth tree"]

To use some real numbers, imagine each movie has 10 actors on average. Each movie will then generate 10^2^ == 100 buckets. If you have 20,000 movies, that's roughly 2,000,000 generated buckets.

Now, remember, our aggregation is simply asking for the top 10 actors and their co-stars, totaling 50 values. To get the final results, we have to generate that tree of 2,000,000 buckets, sort it, and finally prune it such that only the top 10 actors are left. This is illustrated in <> and <>.

[[depth-first-2]] .Sort tree image::images/300_120_depth_first_2.svg["Sort tree"]

[[depth-first-3]] .Prune tree image::images/300_120_depth_first_3.svg["Prune tree"]

At this point you should be quite distraught. Twenty thousand documents is paltry, and the aggregation is pretty tame. What if you had 200 million documents, wanted the top 100 actors and their top 20 costars, as well as the costars' costars?

You can appreciate how quickly combinatorial expansion can grow, making this strategy untenable. There is not enough memory in the world to support uncontrolled combinatorial explosions.

==== Depth-First Versus Breadth-First

Elasticsearch allows you to change the collection mode of an aggregation, for exactly this situation. ((("collection mode"))) ((("aggregations", "preventing combinatorial explosions", "depth-first versus breadth-first")))The strategy we outlined previously--building the tree fully and then pruning--is called depth-first and it is the default. ((("depth-first collection strategy"))) Depth-first works well for the majority of aggregations, but can fall apart in situations like our actors and costars example.

For these special cases, you should use an alternative collection strategy called breadth-first. ((("beadth-first collection strategy")))This strategy works a little differently. It executes the first layer of aggregations, and then performs a pruning phase before continuing, as illustrated in <> through <>.

In our example, the actors aggregation would be executed first. At this point, we have a single layer in the tree, but we already know who the top 10 actors are! There is no need to keep the other actors since they won't be in the top 10 anyway.

[[breadth-first-1]] .Build first level image::images/300_120_breadth_first_1.svg["Build first level"]

[[breadth-first-2]] .Sort first level image::images/300_120_breadth_first_2.svg["Sort first level"]

[[breadth-first-3]] .Prune first level image::images/300_120_breadth_first_3.svg["Prune first level"]

Since we already know the top ten actors, we can safely prune away the rest of the long tail. After pruning, the next layer is populated based on its execution mode, and the process repeats until the aggregation is done, as illustrated in <>. This prevents the combinatorial explosion of buckets and drastically reduces memory requirements for classes of queries that are amenable to breadth-first.

[[breadth-first-4]] .Populate full depth for remaining nodes image::images/300_120_breadth_first_4.svg["Step 4: populate full depth for remaining nodes"]

To use breadth-first, simply ((("collect parameter, enabling breadth-first")))enable it via the collect parameter:

[source,js]

{ "aggs" : { "actors" : { "terms" : { "field" : "actors", "size" : 10, "collect_mode" : "breadth_first" <1> }, "aggs" : { "costars" : { "terms" : { "field" : "actors", "size" : 5 } } } } }

}

<1> Enable breadth_first on a per-aggregation basis.

Breadth-first should be used only when you expect more buckets to be generated than documents landing in the buckets. Breadth-first works by caching document data at the bucket level, and then replaying those documents to child aggregations after the pruning phase.

The memory requirement of a breadth-first aggregation is linear to the number of documents in each bucket prior to pruning. For many aggregations, the number of documents in each bucket is very large. Think of a histogram with monthly intervals: you might have thousands or hundreds of thousands of documents per bucket. This makes breadth-first a bad choice, and is why depth-first is the default.

But for the actor example--which generates a large number of buckets, but each bucket has relatively few documents--breadth-first is much more memory efficient, and allows you to build aggregations that would otherwise fail.

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